Question

A man throws a ball to maximum horizontal distance of 120m.calculate the maximum height reached.​

Answer 1

For maximum distance in horizontal

Q(for throw) from ground=45°

So, R cm = 4² SIn(2Q)/g

R cm= 4² sin(2×45)/g. [ Q= 45]

R cm = 4²/g

= 80=4²/g

= 80 ×10 = 4²

then, 4²=80°

Now, man :high = 4² sin² Q/2g

= 80×1/2÷ 2×10

40×1÷2= 20

so the maximum height reached by the ball is 20 m.

Answer 2

Answer:

r- max = 120m

r.max = 4 H

H = r. max/

=120/4

=30