Question

a man throws a ball to maximum horizontal distance of 80meters. calculate the maximum height reached.​

Answer 1

Answer:

20m

Explanation:

If the ball is thrown to maximum horizontal distance of 80m and the max. Height is attained then angle of projection must be 45 degrees

So now,we have to find speed of projection by range formula:-

R=u^2sin2theta/g

80=u^2sin2(45)/g

as we know sin2theta=2sintheta costheta

Therefore,80=u^2 2×1×1/g×root2×root2

80=u^2×2/2g

800=u^2

U=28.28m/s(approx.)

Now,max.height=u^2sin^2(45)/2g

=>800×1/2×10×2

=>800/40

=>20m