Question

A man throws a ball to maximum
horizontal distance of meters Calculate
the maximum height reached
​

Answer 1

Answer:

Explanation:

∝ = 45°

R = u²sin2∝/g = u²/g

H = u²sin²∝/2g = u²/4g = R/4

Answer 2

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For maximum range,

α=45°

R = u^2 Sin2α/g = u^2 /g

H = u^2Sin^α/g = u^2/4g

H=R/4

the maximum height reached when the maximum distance is one fourth

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