A man throws a ball weighing 500g vertically upwards with a speed of 10m/s. i. What will be its initial momentum? ii. What would be its momentum at the highest point of its flight?
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12
(i)
p=mu
p=initial momentum
m=mass=500g
u=initial velocity=10m/s
p=500*10
p=5000gm/s
ii)
p'=mv
p' =highest movement
m=mass=500g
v=final velocity=0
p'=mv
p'=500*0
p'=0gm/s
plz mark as brainlist answer
p=mu
p=initial momentum
m=mass=500g
u=initial velocity=10m/s
p=500*10
p=5000gm/s
ii)
p'=mv
p' =highest movement
m=mass=500g
v=final velocity=0
p'=mv
p'=500*0
p'=0gm/s
plz mark as brainlist answer
Answered by
3
Answer:
1. Initial momentum is mu=0.5Kg×10m/s=5Kg−m/s
2. At highest point its velocity becomes zero so momentum will slo be zero as momentum p=mass×velocity.
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