A man throws a ball weighting 100g vertically upwards with a speed of20m/s. What will be its initial momentem? What would be its mamentum at the highest point
Answers
Answer:
Initial momentum of ball is 2 kg m / sec .
At highest point momentum is 0 kg m / sec .
Explanation:
Given :
Mass of ball m is 100 g or 0.1 kg
Velocity of ball is 20 m / sec
We know that momentum is nothing but product of mass and
velocity .
i.e. p = m v
Putting values here we get
p = 0.1 × 20 kg m / sec .
p = 2 kg m / sec .
Thus initial momentum of ball is 2 kg m / sec
At highest point velocity will be 0 m / sec
So momentum at the highest point will be
p = m × 0 kg m / sec
p = 0 kg m / sec
At highest point momentum is 0 .
Hence we get answer .
The initial momentum when ball is thrown is 2 kg.m/s.
The momentum at the highest point is 0 kg.m/s.
______________________
Given : Mass of ball = 100g = 0.1 kg
initial velocity (u) = 20 m/s
To find :
- Initial momentum when ball is thrown.
- Momentum at the highest point.
Solution : We know that,
Momentum = mass × velocity
Therefore, initial momentum = mass × initial velocity
Initial momentum = 0.1 × 20
Initial momentum = 2 kg.m/s
______________________
Now,
Momentum at the highest point = mass × final velocity
but final velocity (v) = 0 ( as the ball thrown vertically upward )
Momentum at the highest point = 0.1 × 0
Hence, the momentum at the highest point = 0 kg.m/s