Math, asked by gurusaipratyusha, 10 months ago

A man throws a die until he gets a number
bigger than 3. The probability that he gets 5
in the last throw is​

Answers

Answered by priyanshiojha51
1

Answer:

I think it is 5/6 because there is no frequency

Answered by harendrachoubay
0

P(E) = \dfrac{1}{2} or 0. 5

Step-by-step explanation:

All possible outcomes are:

1, 2, 3, 4, 5 and 6

Total number of possible outcomes = 6

Let E be the event of getting number bigger than 3.

Favourabe outcomes are:

4, 5 and 6

Number of favourable outcomes = 3

P(E) = \dfrac{Number of favourable outcomes }{Total number of possible outcome}

= \dfrac{3}{6}

= \dfrac{1}{2} or 0. 5

∴ P(E) = \dfrac{1}{2} or 0. 5

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