A man travel 2/5th of his journey by train 1/3rd by taxi 1/6 by bus and remaining 10 km on foot find the length of its total journey
Answers
Answered by
9
Let the total length of the journey be 'x' km. the
So, distance travelled by train=2/5x km
Distance travelled by taxi=1/3x
Distance travelled by bus=1/6x
Distance travelled on foot=10 km
ATQ:-
2/5x+1/3x+1/6x+10=x
2/5x+1/3x+1/6x-x+10=0
-1/10x+10=0
10=1/10x
10×10=x
100=x
So, the length of total journey travelled is 100 km
So, distance travelled by train=2/5x km
Distance travelled by taxi=1/3x
Distance travelled by bus=1/6x
Distance travelled on foot=10 km
ATQ:-
2/5x+1/3x+1/6x+10=x
2/5x+1/3x+1/6x-x+10=0
-1/10x+10=0
10=1/10x
10×10=x
100=x
So, the length of total journey travelled is 100 km
Answered by
0
Answer:
Let the total journey be x km
journey by train = 2/5 × x km = 2x /5 km
journey by taxi = 1/3 × x km = x/3 km
journey by bus = 1/6 × x km = x/6 km
remaining journey on foot = 10 km
A/Q
2x/5 + x/3 + x/6 + 10 = x
12x/30 + 10x/30 + 5x/30 + 300/30 = x
27x + 300 = 30x
-30x + 27x = -300
-3x = - 300
minas will be cut
x = 300/3
x = 100 ans
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