Question

a man travelled 1/5 of his journey by train 1/3rd by a taxi 1/6th by a bus and the remaining 10 km on foot​

Answer 1

Step-by-step explanation:

Let the total journey be x km, then

according to the question ;

(2/5) of x = by train

(1/3) of x = by taxi

(1/6) of x = by bus

Remaining = 10 km --> by foot

Remaining distance = x - [(2/5)x+(1/3)x+(1/6)x]

10 = x - [(12+10+5)/30]x

10 = x - (27/30)x

10 = x-(9/10)x

(1/10)x = 10

x = 10×10

x = 100

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Hence the length of the total journey is 100km

Answer 2

Answer:

let the total journey is x km

he travelled by train is x/5km

he travelled by taxi is x/3 km

he travelled by bus is x/6km

remaining 10 km on foot

so,

x/5+x/3+x/6+10=x

=> 6x/30+10x/30+5x/30+10=x

=> (6x+10x+5x)/30-x= -10

=> 21x/30-x= -10

=> (21x-30x)/30= -10

=> -9x= -10×30

=> x=10×30/9

=> x=100/3

total distance =100/3 km=33 1/3 km