a man travelled 2/5 of his journey by bus 3/4 of the remaining by motor bike and the rest by bicycle.if the distance travelled by bicycle is 15 km,find the distance travelled by bus
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Let the length of the total journey be x km
So, according to the question.
2/5th part is travelled by train = 2x/5 km
1/3rd part is travelled by bus = x/3 km
1/4th part is travelled by the car = x/4 km
Remaining 3 km is travelled by foot = 3 km
⇒ 2x/5 + x/3 + x/4 + 3 = x
Taking L.C.M. of the denominators and then solving it (L.C.M. is 60).
⇒ (24x + 20x + 15x + 180)/60 = x
⇒ (59x + 180)/60 = x
⇒ 59x + 180 = 60x
59x - 60x = - 180
⇒ - x = - 180
⇒ x = 180
Hence, length of the total journey is 180 km
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