Question

A man travelled 2/5 th of his journey by train,1/3 rd by taxi 1/6 th by bus and remaining 10 km on foot . find the length of his total journey

plz answer as quick as possible​

Answer 1

Answer:

Yes, 10K is 6.2 miles; a considerable distance.

Let x = total journey distance

by train + by taxi + by bus + by foot = total journey

(2/5)x + (1/3)x + (1/6)x + 10K = x

To get rid of all fractions, multiply by the LCM of the denominators (this is just like finding the Least Common Denominator). LCM = 30

12x + 10x + 5x + 300K = 30x

27x + 300K = 30x [group like terms]

300K = 3x [subtract 27x from both sides]

100K = x [divide both sides by 3]

Answer 2

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A man travelled 2/5 th of his journey by train,1/3 rd by taxi 1/6 th by bus and remaining 10 km on foot . find the length of his total journey.

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➡Total journey of men is 100km.

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• Distance covered by train = 2/5
• Distance covered by taxi = 1/3
• Distance covered by bus = 1/6
• Distance covered by foot = 10km

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• Total journey travelled by men.

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In this question, we have to calculate total journey of men. So, we will find the total journey by

Distance covered by foot = Total Distance - [ Distance travelled by train + Taxi + Bus ]

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Let the total distance be x

So,

Distance covered by train = 2x/5

Distance covered by taxi = 1x/3

Distance covered by bus = 1x/6

Distance covered by foot = Total Distance - [ Distance travelled by train + Taxi + Bus ]

$\bf \implies 10 = x - ( \frac{2}{5} x + \frac{1}{3} x + \frac{1}{6} x)$

$\bf \implies 10 = x - ( \frac{12x + 10x + 5x}{30} )$

$\bf \implies 10 = x - \cancel\frac{27}{30} x$

$\bf \implies 10 = x - \frac{9}{10} x$

$\bf \implies 10 = \frac{10x - 9x}{10}$

$\bf \implies 10 = \frac{x}{10}$

$\bf \implies \frac{x}{10} = 10$

$\bf \implies x = 10 \times 10$

$\bf \implies x = 100km$

Therefore, Total journey travelled by men is 100km.

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