Question

A man travelled 2/5th of his journey by train, 1/3rd by taxi, 1/6 th by bus and ​

Answer 1

Answer:

Step-by-step explanation:

Let the total journey be x km, then

according to the question ;

(2/5) of x = by train

(1/3) of x = by taxi

(1/6) of x = by bus

Remaining = 10 km --> by foot

Remaining distance = x - [(2/5)x+(1/3)x+(1/6)x]

10 = x - [(12+10+5)/30]x

10 = x - (27/30)x

10 = x-(9/10)x

(1/10)x = 10

x = 10×10

x = 100

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Hence the length of the total journey is 100km

Answer 2

Step-by-step explanation:

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$\: let \: the \: length \: of \: his \: journey \: \\ \\ total \: journey \: be \: x \\ so \\ \\ x \: \: \frac{2}{5} x + \frac{1}{3} x + \frac{1}{4} x + 3 = x \\ \\ = ( \frac{2}{5} + \frac{1}{3} + \frac{1}{4} ) - x = - 3 \\ \\ \\ = x \: \: \ ( \frac{2}{5} + \frac{1}{3} + \frac{1}{4} ) - 1 = - 3 \\ \\ = x \: (\frac{2 \times 12 + 20 + 1 \times 15 - 60}{60}) = - 3 \\ \\ = x \: (\frac{24 + 20 + 15 - 60}{60} ) = - 3 \\ \\ = x ( \frac{ - 1}{60} ) = - 3 \\ \\ = \frac{x}{60 } = - 3$

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