Question

A man travelled 3/4 of his journey by bus,1/5 by taxi and remaining 5 km on foot.find the totAl distance of his journey.​

Answer 1

Answer:

traveled distance:-

(3/4×a)+(1/5×a)+5=a

(3a/4)+(1a/5)=a-5

now LCM:-

(5×3a)+(4×1a)/20=a

5×3a+4×1a/20=a

(5+4)+(3a×1a)/20=a

9+3a/20=a

9+3a=20a

9=20a-3a

9=17a

17a=9

a=9/17

a= 0.5294117647

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Answer 2

Answer:

Let the total distance of his journey be X km

$Then, \: the \: total. \: distance \: covered \: by \: bus = \frac{3}{4} of \: x \: km = \frac{3x}{4} \: km$

$the \: distance \: covered \: by \: taxi \: \\ = \frac{1}{5} \: of \: x \: km = \frac{x}{5} km$

$the \: distance \: covered \:on \: foot \: = 5km \\ \\ total \: distance \: = x \: km \\ \frac{3x}{4} + \frac{x}{5} + 5 = x$

Multiplying both sides of the equation by 20, the LCM of 4 and 5, we get

15x + 4x + 100 = 20x

19x + 100 = 20x

20x - 19x = 100

x = 100

✅ hence the total distance of the journey = 100km.