Question

a man travelled 47 1/2 km in one day. he covered 29 1/3 km by scooter 8 5/6 km on bicycle and rest on foot. how much did he travel on foot

Answer 1

Distance travelled on foot= 47 1/2 - 29 1/3 - 8 5/6 = 9 1/3 Km.

Answer 2

hye

=========================================
A man travelled 47 1/2 km in one day

=>47 1/2
=  94  +1/2
 = 95/2km

he covered 29 1/3 km by scooter 8 5/6 km on bicycle and rest on foot

=> 29 1/3                                             =>        8 5/6
= 87+1/3                                                      =  48+5/6
= 88 / 3                                                      = 53/6

so let us form an equation

$\frac{95}{2} = \frac{88}{3} + \frac{53}{6} +foot$

=>$\frac{285}{6} = \frac{176}{6} + \frac{53}{6} +foot$

 => $\frac{285}{6} = \frac{229}{6} +foot$

=> $foot = \frac{285}{6} - \frac{229}{6}$

=>foot = 56/6

foot =  28 /3km

      = $9 \frac{1}{3} km$

===================================

hope it helps u.............