a man travelled 96 km by cycle. He saw that if he travelled with a speed of 2 km/hr more, then he requires 4 hours less. Find the speed of the man. solve by quadratic equation in one variable with sridharn acharyya method.plz help
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Answer:
6km/hr
Explanation:
Let initial speed be x
initial time be t
so as per the formula: S = D/T
x = 96/t or t = 96/x
now new speed = (x+2)
new time = (t-4)
Therefore:
(x+2) = 96/(t-4)
(x+2).(t-4) = 96
(x+2).(96-4x) = 96x
96x - 4x^2 + 192 - 8x = 96x
-4x^2 - 8x + 192 = 0
x^2 + 2x - 48 = 0 (dividing by -4)
x^2 + 8x - 6x - 48 = 0
x(x+8) - 6(x+8) = 0
(x+8)(x-6) = 0
therefore x = -8, x = 6
Since speed can't be negative
x = 6km/hr
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