Question

A man travelled a distance at a speed of 3km/hr and reached 15 min late and travel at speed of 4km/hr and reached 15 min earlier. What is the distance he traveled?

Answer 1

First Case

3km/h = 3*5/18

=5/6 m/s

let the time be t¹

s = d/t

d = s*t

=5/6*

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