A man travelled a distance of 61 miles in 7 hours. He covered a part of the distance at a
speed of 8 miles/ hr and the remaining at a speed of 10 miles/ hr. How long did he travel at 8
miles/ hr?
Answers
Answered by
0
Solution:
Let us understand how we can calculate it-
Let the time in which he travelled on foot=x hr
Then the time in which he travelled on bicycle
=(9−x)=(9−x)hr
distance = speed × time
⇒4x+9(9−x)=61
⇒4x+81−9x=61
⇒5x=20
x=4
⇒4x+9(9−x)=61⇒4x+81−9x=61⇒5x=20⇒x=4
Distance traveled on foot
=4x
=4×4=16 km
=4x=4×4=16 km
Answered by
0
Step-by-step explanation:
Let the time in which he travelled on foot = x hour
Time for travelling on bicycle = (9 - x) hr
Distance = Speed * Time, and Total distance = 61 km
So,
4x + 9(9-x) = 61
=> 5x = 20
=> x = 4
So distance traveled on foot = 4(4) = 16 km
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