Question

A man travelled by car 12 km in 45 minutes. Find his speed in mlsec.
​

Answer 1

Step-by-step explanation:

Given, distance covered = 12 km =12000 m

Time required = 45 min = 45 × 60 s

Speed = distance /time

= 12000/45×60

=12000 /2700

= 4.44 m/s

Hence, speed is 4.44 m/s

Answer 2

Answer:

▪︎Given:

Distance travelled by the car = 12 km

Time travelled by the car to travel the distance = 45 mins

▪︎To find:

Speed of the car in m/sec

▪︎Concept:

See , first find the speed of the car in km / hr .

Then , find the speed of the car in m / sec .

▪︎Taken:

To find the speed in km/hr:

$Sk=D×\frac{60}{T}$

Where,

Sk = Speed in km/hr

D = Distance travelled

T = Time taken

To find speed in m/s:

$Sm=\frac{5}{18}×Sk$

Where,

Sm = Speed in m/s

Sk = Speed in km/hr

▪︎Solution:

First speed in km/hr:

$\implies{Sk=12km×\frac{60}{45}}$

$\implies{Sk=12km×\frac{4}{3}}$

$\implies{Sk=4×4}$

$\implies{Sk=16km/hr}$

____________________________________________

Now , find speed in m/s:

$\implies{Sm=\frac{5}{18}×16km/hr}$

$\implies{Sm=5×0.899(approx)}$

$\implies{Sm=4.45m/s(approx)}$

▪︎Answer:

So , the speed of the car in m/s is 4.45 m/s (approx) .

▪︎Extra information:

To find speed in m/s to km/hr:

$Sk=\frac{18}{5}×Sm$

Where,

Sk = Speed in km/hr

Sm = Speed in m/s

To find the average speed:

$As=\frac{TD}{TT}$

Where,

As = Average speed

TD = Total distance travelled

TT = Total time taken

To find acceleration:

$A=\frac{V1-V}{T}$

Where,

A = Acceleration

V1 = Final velocity

V = Initial velocity

T = Time