Question

A man travelled from A to B at speed of30 km/ hr and returned at a speed of 20 km/hr if the total time is5/4 find distance

Answer 1

Answer:

Average Jeed = 360 / (13 km/h) * r

Average Jeed=27.69 km/hr.

Step-by-step explanation:

ltoB = 20 km/h * r

B to C = 30 km/h * r

Again A to B=40 km/hr.

Formula used:

Speed = Dis * tan c * e / T * i * m * e

Calculations:

Distance is constant so Let, assume the distance LCM of 20, 30 , and 40 = 120 .

prime tance=120 km

→ Time taking from A to B = 120/20 = 6 hour

Time taking from B to C = 120/30 = 4 hour

Time taken from again A to 3 = 120/40 = 3 hour

→ Total dis * tan c * e = 120 + 120 + 120 = 360 km

altime = 6 + 4 + 3 = 13 hour

Average Jeed = 360 / (13 km/h) * r

Average Jeed=27.69 km/hr.