Math, asked by saicharanm244, 8 months ago

a man travelled from Hyderabad to Bangalore he travelled first hundred kilometres in 2 hours and next 150 km in 4 hours and the remaining 200 km in 6 hours. find the average speed?

Answers

Answered by rsultana331
4

Answer:

Answer:

Step-by-step explanation:

Let the total distance be x.

Time = Distance / speed

Distance covered at 80 km/h is :

= 1/3x

Time taken = 1/3x × 1/80 = 1/240x

Distance covered by 60 km/h is :

= 1/4x

Time = 1/4x × 1/60 = 1/240x

Distance covered at 100km/h is :

= 1/6x

Time taken = 1/6x × 1/100 = 1/600x

Distance covered at 50km/h is :

1 - (1/4 + 1/3 + 1/6) = 1/4x

Time = 1/4x × 1/50 = 1/200x

Total time taken is :

1/240x + 1/240x + 1/600x + 1/200x = 3/200x

Average speed = Total distance / Total time

This is given by :

x ÷ 3/200x

= x × 200/3x = 200/3

= 66.67 km/h

Answered by Nishika20
0

Answer:

=Let the total distance be x.

Time = Distance / speed

Distance covered at 80 km/h is :

= 1/3x

Time taken = 1/3x × 1/80 = 1/240x

Distance covered by 60 km/h is :

= 1/4x

Time = 1/4x × 1/60 = 1/240x

Distance covered at 100km/h is :

= 1/6x

Time taken = 1/6x × 1/100 = 1/600x

Distance covered at 50km/h is :

1 - (1/4 + 1/3 + 1/6) = 1/4x

Time = 1/4x × 1/50 = 1/200x

Total time taken is :

1/240x + 1/240x + 1/600x + 1/200x = 3/200x

Average speed = Total distance / Total time

This is given by :

x ÷ 3/200x

= x × 200/3x = 200/3

= 66.67 km/h

Step-by-step explanation:

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