a man travelled one third of a distance by bus, two-fifth by a taxiand the remaining 28 km on scooter. How much distance did he travel?
Answers
Answered by
3
let the distance be x
ATQ,
1/3x + 2/5x + 28 = x
7/15x +28 = x
28 = 8x/15
so x = 15×28/8
hope this helps you out!
ATQ,
1/3x + 2/5x + 28 = x
7/15x +28 = x
28 = 8x/15
so x = 15×28/8
hope this helps you out!
Answered by
1
hi mate ✌️
Let's assume the distance be a.
1/3a + 2/5a + 28 = a
7/15a + 28 = a
28 = 8x/15
So x = 15 × 28/8
= 52.5
Hope it helps ❤️
Let's assume the distance be a.
1/3a + 2/5a + 28 = a
7/15a + 28 = a
28 = 8x/15
So x = 15 × 28/8
= 52.5
Hope it helps ❤️
Similar questions