Question

A man travelled two fifth of his journey by train, one third of his journey by bus , one fourth by car and the remaining 3km on foot. What is the length of his total journey

Answer 1

Solution :-

Let the length of the total journey be x km

So, according to the question.

2/5th part is travelled by train = 2x/5 km

1/3rd part is travelled by bus = x/3 km

1/4th part is travelled by the car = x/4 km

Remaining 3 km is travelled by foot = 3 km

⇒ 2x/5 + x/3 + x/4 + 3 = x

Taking L.C.M. of the denominators and then solving it (L.C.M. is 60).

⇒ (24x + 20x + 15x + 180)/60 = x

⇒ (59x + 180)/60 = x

⇒ 59x + 180 = 60x

59x - 60x = - 180

⇒ - x = - 180

⇒ x = 180

Hence, length of the total journey is 180 km

Answer.

Answer 2

Solution:
Let X be the length of journey.
Man covers 2/ 5 of his journey by train= 2/5 * X= 2X/5

Man covers 1/3 of journey by bus=X/3

Man Covers 1/4:of journey by car=X/4

3km he Overs by walk
So total distance= X=
2X/5 +X/4+X/3+3
Taking L.C.M
X= (24X+15X+20X+180)/60
60X=59X+180
60X-59X=180
X=180km

Hence the length of total jounery is 180km