A man travelled two-fifth of his journey
by train, one-third by bus, one-fourth
by car and the remaining 3 km on foot.
What is the length of his total journey?
Answers
Answered by
5
Answer:
Let the length of his total journey be x
So,
5
2
x+
3
1
x+
4
1
x+3=x
solving
x(
5
2
+
3
1
+
4
1
)−x=−3
=x(
5
2
+
3
1
+
4
1
−1)=−3
=x(
60
2×12+20+1×15−60
)=−3
=x(
60
24+20+15−60
)=−3
=x(
60
−1
)=−3
=
60
x
=3
∴x=180 km
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8
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Answer : Total journey distance is 480 kmLet the distance be ‘X’Distance journey by Car ( X/4) kmDistance journey by Bus ( 2 X/ 3 ) kmHence, the equation is X = [ (X/4) + (2 X/3) + 40] daysX = [ (3 X + 8 X ) / 12 ] + 40( 12 X - 11 X ) = ( 40 x 12 ) days = 480 DaysTotal journey distance is 480 km
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