Question

A man travelled two fifth of his journey by train, one third of his journey by bus , one fourth by car and the remaining 10km on foot. What is the length of his total journey​

Answer 1

Hello there,

Let the total length of his journey be 'x' km

so,

according to the given conditions in the question, we get :

$\frac{2}{5}x + \frac{1}{3}x + \frac{1}{4}x + 10 = x$

now, let's get the variables on one side , and the number part on the other, so we get :

$\frac{2}{5}x + \frac{1}{3}x + \frac{1}{4}x - x= - 10$

Now,

let's take x common on left side,

we get :

$x( \frac{2}{5} + \frac{1}{3} + \frac{1}{4} - 1) = - 10$

take the LCM and we get :

$x( \frac{24 + 20 + 15 - 60}{60}) = - 10$

and then,

$x( \frac{ - 1}{60} ) = - 10$

$- \frac{x}{60} = - 10$

- sign gets cancelled

then,

we get :

$x = 60 \times 10 = 600$

THEREFORE,

TOTAL LENGTH OF HIS JOURNEY = 600km

HOPE THIS HELPS

THANKS