Math, asked by Divya5617, 1 year ago

A man travelled two-fifth of his journey by train, one-third by bus, one-fourth by car and the remaining 3km on foot. what is the length of his total journey?

Answers

Answered by Anonymous
7

Let the length of his total journey be x


According to question,


2/5x + 1/3x + 1/4x + 3 = x

59/60x + 3 = x

x / 60 = 3

x = 180km



Therefore, length of total journey be 180km.




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Answered by Anonymous
2

|| SOLUTION ||

Let total distance travelled be x km.

  \\  \\ \bold{Distance \:  travelled \:  by  \: train  =  \frac{2}{5} \: of \: x \:  =  \frac{2x}{5}  } \\  \\  \bold{Distance  \: travelled \:  by \:  bus =  \frac{1}{3}  \: of \: x =  \frac{x}{3} } \:  \:  \:  \\  \\  \bold{Distance \:  travelled \:  by \:  car =  \frac{1}{4} \: of \: x =  \frac{x}{4}   } \:  \:  \:  \:  \\  \\  \bold{ Distance  \: travelled \:  by  \: foot  = 3km} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

According to the Question,

 \\  \\   \therefore\bf{ \frac{2x}{5} +  \frac{x}{3}   +  \frac{x}{4}  + 3 = x }  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\ \\ \implies \: \bf{ \frac{(2x \times 12) + (20x) + (15x) + (3 \times 60)}{60} = x } \\  \\  \implies \bf{ \frac{24x + 20 x + 15x + 180}{60} } = x \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \implies \bf{ \frac{59x + 180}{60}  = x} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \implies \bf{59x + 180 = 60x} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \implies \bf{180 = 60x - 59x} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \implies \bf \: {x = 180} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\

  \boxed{   \pink\therefore\bf  \: The \:  total  \: distance \:  of \:  the  \: journey  \: is  \: 180 km}

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