a man travelling at a speed of 20 km/ hr reaches his office 10 minutes late . next day he travelled at a speed of 30 km/ hr and he reached his office 10 minutes earliee. the distance between his office and home.....
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Let the distance between his house and office be d and the normal time be t hours.
When he drives at 20 km/h, it takes (t + 1/6) hours and when at 30 kmph, it takes (t – 1/6) hours.
D = 20 * (t + 1/6)
D = 30 * (t – 1/6)
Equating the two equations, we have
20 * (t + 1/6) = 30 * (t – 1/6)
t = 50 mins
Distance = 20 * (1) = 20 kms
The distance between his house and office is 20kms.
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