A man travelling at a speed of 20 km per hour reached his office 10 minute lead next day he travel the at a speed of 30 km per hour and he reached his office 10 minutes earlier the distance between office and home
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d- constant
s. t
20. 30=3×20=60
diff= }1=20
30. 20=2 ×20=40
useual time= 40+10=50 min
d=30×50/60=25 km will be the answer
s. t
20. 30=3×20=60
diff= }1=20
30. 20=2 ×20=40
useual time= 40+10=50 min
d=30×50/60=25 km will be the answer
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