Question

a man travels 10 m to the east, 20 m to the north and then 20√2 m southwest. Find displacement and distance travelled​

Answer 1

Answer:

Displacement = 5.924 m

Distance = 58.28 m

Explanation:

The motion of the man forms a right angled triangle.

Displacement is a vector quantity and therefore has direction and magnitude.

When he travels East to North the displacement will be :

10² + 20² = 500

Square root of of 500 = 10 square root of 5

However he travels 20 square root of 2 South West which means he travels back to the same position and past the position.

The displacement is therefore = 20square root of 2 - 10 square root of 5

= 5.924 m

The total distance = the total length

= 10m + 20m + 20 square root of 2

= 30m + 28.28 m = 58.28 m