Question

A man travels 300 km partly by train and partly by car. He takes 4 hrs. If he travels 60kms by train and rest by car. If he travels 100 km by train and tge remaining by car he takes 10 mins longer . Find the speed of train and car​

Answer 1

Answer:

let the speed of train be X and speed of bus be

y

Step-by-step explanation:

speed =distance /time

4=60/x +240/y.............(1)

4hr 10min =100/x +200/y.......(2)

(1)*5

20=300/x+240*s/y

(2)*3

25*3/62=300/x+600/y

20-25/2=1200/y-600/y

15/2=600/y

y=80km/hr

4=60/x+240/80

x=60km/hr

Answer 2

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$\bf{https://brainly.in/question/37581179}$

Let the speed of train and bus be u km/h and v km/h respectively.

According to the question,

$\frac{60}{u} + \frac{240}{v} = 4$....(i)

$\frac{100}{u} + \frac{200}{v} = 4 + \frac{10}{60} = \frac{25}{6}$....(ii)

Let $\frac{1}{u} = p\: and \frac{1}{v} = q$

The given equations reduce to:

60p + 240q = 4 ....(iii)

100p + 200q = $\frac{25}{6}$

600p + 1200q = 25....(iv)

Multiplying equation (iii) by 10, we obtain:

600p + 2400q = 40....(v)

Subtracting equation (iv) from equation (v), we obtain:

1200q = 15

q = $\frac{15}{1200} = \frac{1}{80}$

Substituting the value of q in equation (iii), we obtain:

60p + 3 = 4

60p = 1

p = $\frac{1}{60}$

:. p = $\frac{1}{u} = \frac{1}{60}$, q = $\frac{1}{v} = \frac{1}{80}$

u = 60 km/h , v = 80 km/h

Thus, the speed of train and the speed of car are 60 km/h and 80 km/h respectively.

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