History, asked by dgdfgtft, 1 year ago

A man travels 370 km, partly by train and partly by car.If he covers 250 km by train and the rest by car, it takes him 4 hours, but if he travels 130km by train and the rest by car he takes 18 min. longer. Find the speed of the train and car.BEST ENTRIES WILL BE GIVEN 'BRAINLIEST ANSWER' TITLE.

Answers

Answered by keshav196
0
let the speed of train be xkm/hr and car be ykm/hr using(d=st)
A/Q,
370/x hr by train
and 250/y by car
so 370/x +250/y=4 ----------(i)
also,
130/x + 490/y=43/10 ----------(ii)
let 1/x=a and1/y=b
then, from (i)
370a+250b=4 ---------(iii)
also,
130a+490b=43/10 '-----------(iv)
On solving (iii) and (iv),we get,
we can find vaule of x and y


hope rest you can solve...
Answered by Likhith11
2
speed of train = X
speed of bus = y
then
250 / X + 120 / y = 4
130 / X + 240 / y= 4 + 18/ 60 {43/10)
Let
1/x=p and 1/y = q. then
250p +120q=4-------(1)
130p+240q=4.3--------(2)
From
these 2 equations ,
p=1/100 and q=1/80
So,p=1/x=1/100 and q=1/y=1/80
Thus,x=100 and y=1/80
speed of train =100km/h
speed of car = 80km/h
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