Question

A man travels 400 km partly by train and partly by car. If he covers half the distance by train and the rest by car, it takes him 4 hours 30 minutes. But if he travels 100 km by train and the rest by car, he takes 15 minutes longer. Find the speed of the train and that of the car. please ans fastt

Answer 1

Let speed of train = x

t speed of train = xThus, speed of car = y

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Thus, 200/x + 200/y = 4.5 { 4 hrs. and 30 minutes}

s, 200/x + 200/y = 4.5 { 4 hrs. and 30 minutes} Let a = 1/x , b = 1/y

t a = 1/x , b = 1/y 200a + 200b = 4.5 (1)

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Similarly

Similarly100a + 300b = 4.75 (2)

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Multiplying 2 throughout (2)

ultiplying 2 throughout (2)200a + 600b = 9.5 (2)

ultiplying 2 throughout (2)200a + 600b = 9.5 (2) By elimination method

ultiplying 2 throughout (2)200a + 600b = 9.5 (2) By elimination method - 400b = -5

ultiplying 2 throughout (2)200a + 600b = 9.5 (2) By elimination method - 400b = -5 b = 5 /400

ultiplying 2 throughout (2)200a + 600b = 9.5 (2) By elimination method - 400b = -5 b = 5 /400 b = 1/80

ultiplying 2 throughout (2)200a + 600b = 9.5 (2) By elimination method - 400b = -5 b = 5 /400 b = 1/80 Thus, y = 80

us, y = 80 Speed of car = 80 km/h

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Substituting b in (1)

bstituting b in (1) 200a + 200b =4.5

bstituting b in (1) 200a + 200b =4.5 200a + 200/80 = 4.5

bstituting b in (1) 200a + 200b =4.5 200a + 200/80 = 4.5 200a + 2.5 = 4.5

bstituting b in (1) 200a + 200b =4.5 200a + 200/80 = 4.5 200a + 2.5 = 4.5 200a = 2

Thus a = 1/100

us a = 1/100 Thus x = 100 km/h

us x = 100 km/h Thus, speed of the train is 100 km/h

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Answer 2

Answer:

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