A man travels 600km by train and car. If he covers 400km by train and rest by car it takes 6hrs &30mins. If he travels 200km by train and rest by car. It takes half an hour longer. Find the speed of train and car...
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Answered by
3
Let x=train speedLet y = car speed
speed = distance / time time = distance / speed
6 hours 30 minutes = 6.5 hours <== 400 km by train ; 200 km by car 1/2 hour longer = 7 hours <== 200 km by train ; 400 km by car
Train time + car time = total time
400 / x + 200 / y = 6.5 <== two equations and two unknowns 200 / x + 400 / y = 7 . . . . . . solve for x and y
400y + 200x = 6.5 xy 200y + 400x = 7 xy
400y - 6.5 xy = - 200x 200y - 7xy = - 400x
y ( 400 - 6.5x) = -200x y ( 200 - 7x) = -400x
y (6.5x - 400) = 200x y (7x - 200) = 400x
y = 200x / (6.5x - 400) y = 400x / (7x - 200) . . . note this equation ... for later use
. . . since both equal y, the difference is zero
200x / (6.5x - 400) - 400x / (7x - 200) = 0
200x ( 7x - 200) - 400x (6.5x - 400) = 0
1400x^2 - 40000x - 2600x^2 + 160000x = 0
120000 x - 1200 x^2 = 0
100 - x = 0
x = 100 km / h <===== train speed
y = 400x / (7x - 200) . . . see note above
y = 400 * 100 / (7 * 100 - 200)
y = 80 km / h <===== car speed
hope I helped u
thank u
speed = distance / time time = distance / speed
6 hours 30 minutes = 6.5 hours <== 400 km by train ; 200 km by car 1/2 hour longer = 7 hours <== 200 km by train ; 400 km by car
Train time + car time = total time
400 / x + 200 / y = 6.5 <== two equations and two unknowns 200 / x + 400 / y = 7 . . . . . . solve for x and y
400y + 200x = 6.5 xy 200y + 400x = 7 xy
400y - 6.5 xy = - 200x 200y - 7xy = - 400x
y ( 400 - 6.5x) = -200x y ( 200 - 7x) = -400x
y (6.5x - 400) = 200x y (7x - 200) = 400x
y = 200x / (6.5x - 400) y = 400x / (7x - 200) . . . note this equation ... for later use
. . . since both equal y, the difference is zero
200x / (6.5x - 400) - 400x / (7x - 200) = 0
200x ( 7x - 200) - 400x (6.5x - 400) = 0
1400x^2 - 40000x - 2600x^2 + 160000x = 0
120000 x - 1200 x^2 = 0
100 - x = 0
x = 100 km / h <===== train speed
y = 400x / (7x - 200) . . . see note above
y = 400 * 100 / (7 * 100 - 200)
y = 80 km / h <===== car speed
hope I helped u
thank u
janakibaiju:
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Answered by
1
Given
Total distance = 600 km
Consider speed of Train = x km/h
Consider speed of Car = y km/h
According to the question:
We know Time = distance/speed
Situation 1
He takes 8 hours if he travels 120 km by train and rest by car
120/x + 480/y = 8-------(1)
Situation (2)
when he travels 200 km by train and rest by car he takes 8 hr 20 min
8 hr 20 min = 25/3 hr
200/x + 400/y = 25/3 ---------(2)
solve equation 1 and 2
you'll get x = 60
so the speed of the train = 60 km/h
There's an alternate method too:
Le the speed of the train be x km/hr and speed of car be y km/hr
Vijay travels 120 km by train, the distance covered by car 600-120 = 480 km
Now, time taken to cover 120 km by train = 120/xhr
And time taken to cover 480 km by car = 480/y
Total time taken to travel 600 km = 120/x + 480/y = 8 hr (i)
Similarly
200/x + 400/y = 8hr. 20minute = 8(20/60) (ii)
solve (i) and (ii)
we get
x = 60 km/hr and y = 80 km/hr
∴ Speed of train 60 km/hr
Hope This Helps :)
Total distance = 600 km
Consider speed of Train = x km/h
Consider speed of Car = y km/h
According to the question:
We know Time = distance/speed
Situation 1
He takes 8 hours if he travels 120 km by train and rest by car
120/x + 480/y = 8-------(1)
Situation (2)
when he travels 200 km by train and rest by car he takes 8 hr 20 min
8 hr 20 min = 25/3 hr
200/x + 400/y = 25/3 ---------(2)
solve equation 1 and 2
you'll get x = 60
so the speed of the train = 60 km/h
There's an alternate method too:
Le the speed of the train be x km/hr and speed of car be y km/hr
Vijay travels 120 km by train, the distance covered by car 600-120 = 480 km
Now, time taken to cover 120 km by train = 120/xhr
And time taken to cover 480 km by car = 480/y
Total time taken to travel 600 km = 120/x + 480/y = 8 hr (i)
Similarly
200/x + 400/y = 8hr. 20minute = 8(20/60) (ii)
solve (i) and (ii)
we get
x = 60 km/hr and y = 80 km/hr
∴ Speed of train 60 km/hr
Hope This Helps :)
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