Math, asked by naitiksingh23, 1 month ago

A man travels 800 km partly by train and partly by car. It takes 13 hours and 45 minutes if he travels 450 km by train and rest by car. It would take 125 minutes more if he travels 300 km by train and rest by car, then the ratio of speeds of car and train is​

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Answered by nav998
2

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Answered by Agastya0606
0

The ratio of the speed of the car and train will be 4/9.

Given,

A man travels 800 km partly by train and partly by car. It takes 13 hours and 45 minutes if he travels 450 km by train and rest by car. It would take 125 minutes more if he travels 300 km by train and rest by car.

To Find,

The ratio of the speed of car and train.

Solution,

Let us assume that the speed of the train is x km/min and the speed of the car is y km/min.

Now,

13 hours 45 minutes = 825 minutes

According to the question

450/x+350/y = 825

18/x+14/y = 33---(i)

And

300/x+500/y = 950

6/x+10/y = 19, multiplying this equation by 3

18/x+30/y = 57---(ii)

(ii)-(i)

16/y = 24

y = 16/24 = 2/3

putting the value of y in (i)

18/x+14(3/2) = 33

18/x = 33-21

18/x = 12

x = 18/12 = 3/2

Now, the ratio of speed of car and train will be

y/x = (2/3)/(3/2) = 4/9

Hence, the ratio of the speed of the car and train will be 4/9.

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