A man travels 900km ay 60kmph he then travels anither 600km at 40kmph what is the avg speed
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here is your answer
given :
distance1 = 900 km
speed1 = 60 km/hr
distance2 = 600 km
speed2 = 40 km/hr
to find : average speed
solution :
avg. speed = (d1+d2)/(t1+t2)
avg. speed = (d1+d2)/[(d1/v1)+(d2/v2)]
avg. speed = (900+600)/[(900/60)+(600/40)]
avg. speed = 1500/(15+15)
avg. speed = 1500/30
avg. speed = 50 km/hr
so, the average speed is of 50 km/hr.
given :
distance1 = 900 km
speed1 = 60 km/hr
distance2 = 600 km
speed2 = 40 km/hr
to find : average speed
solution :
avg. speed = (d1+d2)/(t1+t2)
avg. speed = (d1+d2)/[(d1/v1)+(d2/v2)]
avg. speed = (900+600)/[(900/60)+(600/40)]
avg. speed = 1500/(15+15)
avg. speed = 1500/30
avg. speed = 50 km/hr
so, the average speed is of 50 km/hr.
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