Question

A man travels a distance 8 m towards north then
turs left and moves towards west 6 m. What is
the total distance and displacement from the
starting point of his journey?
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Answer 1

${\large{\pmb{\underline{\sf{RequirEd \: solution...}}}}}$

${\bigstar \:{\pmb{\underline{\sf{About \: Question...}}}}}$

⋆ Correct question: A man travels a distance 8 m towards north then turns left and moves towards west 6 m. What is the total distance and displacement from the starting point of his journey?

⋆ Understanding the question: This question says that there is man who is travelling to a distance of 8 metres to the north direction afterthat he turns to west direction that is on the left side at the distance of 6 metres. Now this question says that we have to find out the distance and the displacement also from the starting point of his journey.

${\bigstar \:{\pmb{\underline{\sf{Given \: that...}}}}}$

⋆ A man travels a distance 8 metres towards the North direction.

⋆ Then turns left and moves towards the West direction 6 metres

${\bigstar \:{\pmb{\underline{\sf{To \: find...}}}}}$

⋆ The total distance from the starting point of his journey.

⋆ The displacement from the starting point of his journey.

${\bigstar \:{\pmb{\underline{\sf{Solution...}}}}}$

⋆ The total distance from the starting point of his journey = 14 metres

⋆ The displacement from the starting point of his journey = 10 metres

${\bigstar \:{\pmb{\underline{\sf{Using \: concepts...}}}}}$

⋆ To find the total distance we have to add the both distances together.

⋆ Phythagoras theorm.

${\bigstar \:{\pmb{\sf{\underline{Full \: Solution...}}}}}$

~ Finding total distance first

»»» First distance = 8 metres

»»» Second distance = 6 metres

»»» Total distance = (8 + 6) metres

»»» Total distance = 14 metres

~ Now finding total displacement

»»» (B)²= (6)² + (8)²

»»» (B)² = 36 + 64

»»» (B)² = 100

»»» B = √100

»»» B = 10 metres

»»» Displacement = 10 metres