a man travels a distance of 196 km by train and returns in a car which travels at a speed of 21 km /hr more than the train. if the total journey takes 11 hrs, find the average speed of the train and the car respectively
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speed of train=x
speed of car =x+21
(196/x) +(196/x+21)=11
by solving this u get x=28km/hr
speed of car =x+21
(196/x) +(196/x+21)=11
by solving this u get x=28km/hr
Answered by
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Let speed of train =x km/hr. so speed of car = x+21. km/hr. A.T.Q.). 196/x +196/21+x =11
196(21 +x)+196x/x(21+x)=11. now please solve.
196(21 +x)+196x/x(21+x)=11. now please solve.
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