Physics, asked by shrutidgp1311, 2 months ago

A man travels a distance of 3 m towards East, then 4 m towards North. (i) What is the total distance travelled by the man? (ii) What is the total displacement?

Answers

Answered by ritikupadhyay8337
0

Answer:

total distance travelled = 3+4=7. and displacement is the distance between the initial and fit position of the object so displacement in this case is also 3+4=7

Answered by Anonymous
12

AnsWer :

The man is travelling a distance of 3 m towards East and then travel's 4 m towards North. Therefore, the total distance travelled by the man will be:

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T O T A L D I S T A N C E :

↠Total Distance = Distance travelled in East direction + Distance travelled in North direction

↠Total Distance = 3 m + 4 m

Total Distance = 7 m

The total distance travelled by the man is 7 m.

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The shortest distance travelled by the body between it's final point and initial point is called as displacement. By observing the figure, The initial point is A and final point is C. By Pythagorean theorem we can calculate the total displacement:

• T O T A L D I S P L A C E M E N T :

⇥(AC)² = (AB)² + (BC)²

⇥(AC)² = (3)² + (4)²

⇥(AC)² = 9 + 16

⇥(AC)² = 25

⇥AC =√25

AC = 5 m

The total displacement of the man is 5 m.

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