A man travels a distance of 480 km at a uniform speed if the speed had been 8 km per hour less then it would have taken 3 hours more for the same distance find the speed of the train
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Distance = 480 km
Let say Usual Speed = S km/Hr
Decreased Speed = S-8 km/Hr
Time Taken with Usual Speed = 480/S Hr
Time Taken with Decreased Speed = 480/(S-8) Hr
480/(S-8) - 480/S = 3
480S - 480(S-8) = 3S(S-8)
480S + 3840 -480S = 3S²-24S
3S²-24S+3840=0
S²-8S-1280=0
S²-40S+32S-1280 = 0
(S-40)(S+32) = 0
S = 40 as it can not be negative
S = 40 km/Hr
Usual speed = 40 km/Hr
Decreased Speed = 40 -8 = 32 km/Hr
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