Math, asked by shrutisingh8699, 1 month ago

A man travels at a speed of 15 kom hr. If he increases his speed by 33.3%. He can cover 60 km more in the same time. Find the actual distance travelled by him. 1. 120 km 2. 75 km 3. 180 km 4. 270 km​

Answers

Answered by pratikr864
1

Answer:

Man's rate in still water =(15−2.5)km/hr=12.5km/hr

Man's rate against the current =(12.5−2.5)km/hr=10km/hr

Answered by arshikhan8123
0

Concept:

Speed is the rate of change of distance with respect ot time

Distance is the total distance travelled

Time is the time taked to complete the given distance

Speed =distance/ time

Given:

A man travels at a speed of 15 kom hr. If he increases his speed by 33.3%. He can cover 60 km more in the same time.

Find:

the actual distance travelled by him.

1. 120 km 2. 75 km 3. 180 km 4. 270 km​

Solution:

Let the distance he can travel is x

t₁=distance/speed

  =x/15 hr

Again,

Speed=15+15x33.3%

           =15(1+0.333)

           =20km/hr

t₂=distance/speed

 =(x+60)/20 hr

As per question:

t₁=t₂

⇒x/15=(x+60)/20

⇒4x=3x+180

⇒x=180km

Therefore, the actual distance travelled by him is 180 km i.e option 3

#SPJ3

 

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