A man travels at a speed of 15 kom hr. If he increases his speed by 33.3%. He can cover 60 km more in the same time. Find the actual distance travelled by him. 1. 120 km 2. 75 km 3. 180 km 4. 270 km
Answers
Answer:
Man's rate in still water =(15−2.5)km/hr=12.5km/hr
Man's rate against the current =(12.5−2.5)km/hr=10km/hr
Concept:
Speed is the rate of change of distance with respect ot time
Distance is the total distance travelled
Time is the time taked to complete the given distance
Speed =distance/ time
Given:
A man travels at a speed of 15 kom hr. If he increases his speed by 33.3%. He can cover 60 km more in the same time.
Find:
the actual distance travelled by him.
1. 120 km 2. 75 km 3. 180 km 4. 270 km
Solution:
Let the distance he can travel is x
t₁=distance/speed
=x/15 hr
Again,
Speed=15+15x33.3%
=15(1+0.333)
=20km/hr
t₂=distance/speed
=(x+60)/20 hr
As per question:
t₁=t₂
⇒x/15=(x+60)/20
⇒4x=3x+180
⇒x=180km
Therefore, the actual distance travelled by him is 180 km i.e option 3
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