Physics, asked by simransandhugmail, 1 year ago

A man travels distance of 1.5m toward east ,then 2.0m towards south and finally 4.5m toward east in 4s . calculate the (a) total distance travel and (b) the final displacement

Answers

Answered by BRAINLYY
465
TOTAL DISTANCE TRAVELED WILL BE = 1.5 + 2 + 4.5
                                                                  = 8 m

FINAL DISPLACEMENT WILL BE =
We can directly make a diagram for 6 m east and 2 m south, the resultant will be same.

Final Displacement = √ ( 6 square + 2 square )
                               =  √ ( 36 + 4 )
                               = 40 m

ANSWER = (a) 8 m
                    (b) √40 m

HOPE IT HELPS ::):):):)
MARK AS BRAINLIEST
Answered by ankhidassarma9
2

Answer:

(a) Total distance travel is 8m.

(b) final displacement is 6.3245 m

Explanation:

(a) Total distance travel by the man = distance travels in the east direction + distance travels towards the south direction + distance travels in the east direction again

= 1.5 m + 2 m + 4.5 m

= 8m

(b) Let the starting point of that person be A.

He travels towards east from A to point B , then towards south from B to point C and finally from point C to to point D towards east.

To calculate total displacement, we can consider total distance travels towards east together.

Hence Total displacement toward east from point A to B = 1.5 + 4.5 = 6 m

total displacement toward south from B to C = 2m

If we draw a right angle triangle ABC with AB = 6 m and BC = 2m, then the final displacement will be represented by the hypotenuse (AC) of the triangle ABC.

AC = sq. root of ( 6 square + 2 square)

= square root of(36+4)

= 6.3245 m

So the final displacement is 6.3245 m

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