Question

a man travels for 10 hours first half at 21km/hr. and the rest at 20 km/hr find the distance covered

Answer 1

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Distance covered in first half = 5 × 21 = 105 km.
Distance covered in second half = 5 × 20 = 100 km.

Total distance covered = 105 + 100

= 205 km.

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Answer 2

here T₁=10 h             T₂=?
S₁=21 km/h               s₂=20 km/h

using this
T₁:T₂::s₁:s₂
T₂*s₁=T₁*s₂
T₂=(10*20)/21
=200/21
=9.50h
=9+50/60 h
=59/6 h
DIstance= 21x10 + 20*(59/6) 
=210+1180/6
=210+196.67
=406.6 km