Question

A man travels for 5 hours 15minutes .if he covers the first half of the journey at 60km/hr and the rest at 45km/ hr. find the total distance travelled

Answer 1

Answer:

Step-by-step explanation:

Let time taken to travel the first half = x hr

 

Then time taken to travel the second half = (5 - x) hr 

Distance covered in the first half= 60x (Distance =speed x time)

distance covered in the second half= 45(5-x)

So,

the distance covered in first half = the distance covered in second half

so,

=>60x=45(5-x)

=>60x=225-45x

=>60x+45x=225

=>105x=225

=>x=225/105

=>x=15/7

Total distance=2*60(15/7) =120*15/7=257.14km

(multipled by 2 because as 60x the distance is half way)

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Answer 2

Average speed =2×60×4560+452×60×4560+45

=108021108021 km/hr

Time = 5+14 hr=214 hr5+14 hr=214 hr

Distance travelled

=108021×214=270108021×214=270 km