Question

a man travels from his home to office at 4km/hr and reaches his office 20min late. if the speed had been 6km)hr he would have reached 10 min early. Find the distance from his home to office .​

Answer 1

Explanation:

Remember the formula x=vt.

In the 1st case,he reaches 20mint=20/60 hr=1/3 hr late.

So x=4(t+1/3)

Or,3x=4(3t+1)

Or,3x=12t+4

In the second case he take 10 mintutes=10/60 hr=1/6 hr less to reach.

So x=6(t-1/6)

Or,6x=36t-6

Multiply the 1st equation by 3 and then subtract from equation 2.You will get

Please approve the answer if you are helped

-3x=-18

Or,x=6

x=6km

Answer 2

Answer:

Say the time within which he should reach is t hr.

Remember the formula x=vt.

In the 1st case,he reaches 20mint=20/60 hr=1/3 hr late.

So x=4(t+1/3)

Or,3x=4(3t+1)

Or,3x=12t+4

In the second case he take 10 mintutes=10/60 hr=1/6 hr less to reach.

So x=6(t-1/6)

Or,6x=36t-6

Multiply the 1st equation by 3 and then subtract from equation 2.You will get

Please approve the answer if you are helped

-3x=-18

Or,x=6

x=6km