Question

A man travels from home to town and back in a motor cycle.he travels to home from town at a speed which is 20km/hour more than his journey to the town from home .the average speed of his total journey was 48 km/hour
(A) If the distance from home to town is 5 KM find his total journey
(B) bymtime by taking the seed of the journey from home to town as "x" from a second degree equation.

Answer 1

Step-by-step explanation:

Given  

A man travels from home to town and back in a motor cycle.he travels to home from town at a speed which is 20 km/hour more than his journey to the  town from home .the average speed of his total journey was 48 km/hour

(A) If the distance from home to town is 5 KM find his total journey

• Let the speed from home to town be x
• Time taken from home to town = 5/x
• Time taken from town to home = 5 / x + 20
• Average speed = total distance / total time
• 48 = 5 + 5 / 5/x + 5/x + 20
• 48 = 10 x(x + 20) / 5x + 100 + 5x
• So 48(10 x + 100) = 10 x^2 + 200 x
• So 480 x + 4800 = 10x^2 + 200 x
• 10 x^2 – 280 x – 4800 = 0
• Or x^2 – 28 x – 480 = 0  
• So x^2 – 40 x + 12 x – 480 = 0
• Or x (x – 40) + 12 (x – 40) = 0
• So x = 40, - 12
• So x = 40 km/hr
• Now total time will be 5/40 + 5/ 40 + 20
•                           = 5/24

                        = 0.208 hr

Reference link will be

https://brainly.in/question/2642394

Answer 2

Answer:

the answer is 3.60 if you are doing this on Khan Academy