Physics, asked by Manjuddevi, 4 months ago

A man travels on a straight and covers three distance with time intervals in 1:2:3 and with speed v1, v2, v3. Find his average spead ​

Answers

Answered by shardulKhekale
1

Answer:

this is the answer

Explanation:

The equation is simple to derive.

Case 1: When a Body covers distance lets say ‘D’ with speed ‘v1’ time taken can calculated by the following formula.

t1 = D/v1 , ……(1)

Case 2: When a Body covers distance lets say ‘D’ with speed ‘v2’ time taken can calculated by the following formula.

t2 = D/v2 , ……(2)

Case 3: When a Body covers distance lets say ‘D’ with speed ‘v3’ time taken can calculated by the following formula.

t3 = D/v3 , ……(3)

Adding up all the three statements we can get the total time taken by the body which comes out to be

t1 + t2 + t3 ;

or D/v1 + D/v2 + D/v3 ……..(4)

And the total distance covered by the body can be easily calculated as 3D.

So Applying the formula of Average velocity or speed,

Average velocity = Total distance covered/ Total Time Taken the body

Average velocity = 3D / (D/v1 + D/v2 + D/v3)

Solving out the equation results comes out to be:

(3 * v1 * v2 * v3) / (v1v2 + v2v3 + v3v1)

Hope the formula helps

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