a man travels one third length of a straight road with a constant speed 40 m s and the remaining portion of the road with a constant speed of 60ms and then calculate it's average speed
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avg speed for this question is 51.42km/h
formula of avg speed is 3(V1.V2) / 2V1 + V2.
where V 1 equals to 40 and V2 equals to 60.
formula of avg speed is 3(V1.V2) / 2V1 + V2.
where V 1 equals to 40 and V2 equals to 60.
ashish771:
suppose x = distance
v= velocity
now
avg speed= x whole upon x/3V1 + 2x/3V2
if you slove that you will get 3V1V2 upon 2V1 +V2
V1 = 40 and V2 = 60 place the value and you will get the answer
thank you so much
it's ok
In which class you are
I m in 11th
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