Question

A man travels the first part of his journey at 30 km/h and the next at 90 km/h, covering the
entire journey at an average speed of 50 km/h. What is the ratio of the distance that he
covered at 30 km/h to that he covered at 90 km/h:
a)1:4
b)1:3
c)2:3
d) 3:2​

Answer 1

Step-by-step explanation:

Man travels first part of his journey at 30km/h

And the next part at 90km/h

The ratio of the distance that he covered at 30km/h

= 30÷90 =1/3 =1:3 (B) 1:3 is the answer

Answer 2

The given question is A man travels the first part of his journey at 30 km/h and the next at 90 km/h, covering the entire journey at an average speed of 50 km/h.

we have to find What is the ratio of the distance that he covered at 30 km/h to that he covered at 90 km/h.

The solution to this problem is that use the ratio and proportion logic.

The answer must be given in these options, the options are

a)1:4

b)1:3

c)2:3

d) 3:2

firstly the speed was 30 km per hour and a certain distance is covered.

let the distance covered with this speed be x.

The second speed is 90 km per hour.

The distance covered with this speed will be y.

$30 = x \\ 90 = y \\ \frac{30}{90} = \frac{x}{y} \\ \frac{1}{3} = \frac{x}{y}$

The ratio of the distance covered with these speeds 30 and 90 km per hour is found to be 1:3.

Therefore, the correct option to the given question is b, which is 1:3

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