Question

A man travels three-fifths of distance ab at a speed of 3a, and the remaining at a speed of 2b. if he goes from b to a and back at a speed of 5c in the same time, then:

Answer 1

Hello,

Following is the answer to the question above. Hope it helps.

Let the distance between A and B is X

Three-fifths of distance AB =3X/5

Remaining distance=1-3x/5=2X/5

If he goes from A to B and back then total distance X+X=2X

and 2*[((3X/(5*3a))+(2x/(5*2b))]

Now acc. to question

2*[(3X/(5*3a))+(2x/(5*2b))]=2X/5c

solve it and you get 1/a+1/b=1/c

Thanks and regards.

Answer 2

Answer:

HOPE THE ABOVE GIVEN ATTACHMENT WILL HELP YOU......