A man travels with a speed 30 kmph for first half of the journey time and with a speed of 70 kmph for the next half of the journey time. Find the average speed of the man is
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Answer :-
Let us assume that the car has to travel a total distance of 2x km
We know Distance = speed × time
Time = distance/speed ☆
If a car travels the first half of a distance with a speed of 30km/h
- Distance = first half distance means 2x/2 = x km
- Speed = 30 km/hour
Time taken in travel first half of the distance = x km/30 km per hr. = x/30 hrs.
The car cover the remaining half distance with a speed of 70km/h.
- Distance = x km.
- Speed = 70 km/hour
Tine taken to cover second half of the distance = x km/70 km per hr = x/70 hours
Total time taken by car to cover 2x km distance = x/30 + x/70 = 100x/2100 hrs.
Average speed of car = Total distance/total time
Average speed of car = 2x km /100x/2100 hour
⇒2x × 2100/100x
⇒4200x/100x
⇒4200/100
Average speed of car = 42 km/hour
- the average speed of the car was 42 km / hour
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6
Answer:
AVERAGE SPEED OF CAR WAS 42KM/H
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