A man uses a pulley system to raise a load of 100 kg to a height of 10 m. He exerts a force of 60 kg newton on the rope over a distance of 25m. What is the efficiency of the system? (g=10 Nkg-1)
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Given A man uses a pulley system to raise a load of 100 kg to a height of 10 m. He exerts a force of 60 kg newton on the rope over a distance of 25 m. What is the efficiency of the system?
- Now a pulley system is used to raise a load of 100 kg to a height of 10 m.
- So work is done by the man
- So we have W = F x S
- = 60 x 25
- = 1500 kg-m
- Now W out = F out x d out
- = 100 x 10
- = 1000 kg-m
- So Efficiency = W out /W in
- = 1000 / 1500
- = 0.66
- = 66%
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