Question

a man walk 20m towards the East and then turns at an angle of 60 degree towards the north of East and again walks 20 m calculate the net displacement of the men and also find the direction of the net displacement​

Answer 1

Answer:

net displacement = final - initial position

= 20 - 20 =0;

now,

20 m is base and other 20 m is perpendicular left hypotenuse so, h^2 = p^2 + b^2

h^2 = 20*20 + 20*20

h= √800

Answer 2

Answer:

Net displacement of the men is $20.95m$ and direction is from east to north.

Explanation:

It is given that a man walk $20m$ towards the East and then turns at an angle of $60$ degree towards the north of East and again walks $20 m$.

We need to determine displacement of the men and also find the direction of the net displacement​.

From above information,

$r=20m$

Distance/Circumference of circle $=2*pi*r=2*\frac{22}{7} *20=125.7m$

It is for complete $360^{0}$ rotation.

For $60$ degrees,

$=\frac{125.7}{6} =20.95m$

Hence,  net displacement of the men is $20.95m$.

Direction is from east to north.

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